Liz Watson
U.S. House candidate
- Born
- December 9, 1975
- Current age
- 50
- Home state
- Indiana
- Party
- Democratic
- On the ballot
- 2018
0-1
RecordWin–Loss
Total Popular Votes
Watson118,090
Opponents153,271
1
Elections run
Liz Watson, a Democratic politician from Indiana, ran once for U.S. office, losing the 2018 U.S. House election in Indiana's District 9 to Trey Hollingsworth, receiving 118,090 votes (43.52%).
Browse every U.S. House race in Indiana's District 9 or all 2018 U.S. House races.
How many votes has Liz Watson received?
Liz Watson has received 118,090 popular votes across 1 U.S. election, with a career record of 0–1.
Election history
| Year | Office | Result | Votes | Opponent(s) |
|---|---|---|---|---|
| 2018 | U.S. HouseIndiana | Lost | 118,09043.52% | Trey Hollingsworth |
Identity & sources. Identity verified against Wikidata (Q48809277). Election results come from official certified totals and the MIT Election Data and Science Lab; see methodology.
Cite this profile. PolitiFinder, “Liz Watson: election history & vote totals.” https://politifinder.com/p/liz-watson. Accessed [date].