Alfred Hurst
U.S. House candidate
- Born
- November 19, 1846
- Died
- March 25, 1915
- Age at death
- 68
- Home state
- Iowa
- Party
- Democratic
- On the ballot
- 1896
0-1
RecordWin–Loss
Total Popular Votes
Hurst19,882
Opponents24,071
1
Elections run
Alfred Hurst (1846–1915), a Democratic politician from Iowa, ran once for U.S. office, losing the 1896 U.S. House election in Iowa's District 2 to George Curtis, receiving 19,882 votes (45.23%).
Browse every U.S. House race in Iowa's District 2 or all 1896 U.S. House races.
How many votes has Alfred Hurst received?
Alfred Hurst has received 19,882 popular votes across 1 U.S. election, with a career record of 0–1.
Election history
| Year | Office | Result | Votes | Opponent(s) |
|---|---|---|---|---|
| 1896 | U.S. HouseIowa | Lost | 19,88245.23% | George Curtis Charles A Lloyd M J Kremer |
Identity & sources. Identity verified against Wikidata (Q116935097). Election results come from official certified totals and the MIT Election Data and Science Lab; see methodology.
Cite this profile. PolitiFinder, “Alfred Hurst: election history & vote totals.” https://politifinder.com/p/alfred-hurst. Accessed [date].