Margaret Trowe
U.S. Senate candidate
- Born
- January 1, 1948
- Current age
- 78
- Home state
- Iowa
- Party
- Socialist Workers
- On the ballot
- 1998
0-1
RecordWin–Loss
Total Popular Votes
Trowe2,542
Opponents945,090
1
Elections run
Margaret Trowe, a Socialist Workers politician from Iowa, ran once for U.S. office, losing the 1998 U.S. Senate election in Iowa to Charles E. Grassley, receiving 2,542 votes (0.27%).
Browse every U.S. Senate election in Iowa or all 1998 U.S. Senate races.
How many votes has Margaret Trowe received?
Margaret Trowe has received 2,542 popular votes across 1 U.S. election, with a career record of 0–1.
Election history
| Year | Office | Result | Votes | Opponent(s) |
|---|---|---|---|---|
| 1998 | U.S. SenateIowa | Lost | 2,5420.27% | Charles E. Grassley David Osterberg Susan Marcus |
Identity & sources. Identity verified against Wikidata (Q6759970). Election results come from official certified totals and the MIT Election Data and Science Lab; see methodology.
Cite this profile. PolitiFinder, “Margaret Trowe: election history & vote totals.” https://politifinder.com/p/margaret-trowe. Accessed [date].