John A. Mead
★ Governor
- Born
- April 20, 1841
- Died
- January 12, 1920
- Age at death
- 78
- Home state
- Vermont
- Party
- Republican
- On the ballot
- 1910
1-0
RecordWin–Loss
Total Popular Votes
Mead35,263
Opponents17,425
1
Elections run
John A. Mead (1841–1920), a Republican politician from Vermont, ran once for U.S. office, winning the 1910 governor election in Vermont with 35,263 votes (64.2%), defeating Charles D. Watson.
Browse every governor election in Vermont or all 1910 governor races.
How many votes has John A. Mead received?
John A. Mead has received 35,263 popular votes across 1 U.S. election, with a career record of 1–0.
Election history
| Year | Office | Result | Votes | Opponent(s) |
|---|---|---|---|---|
| 1910 | GovernorVermont | Won | 35,26364.2% | Charles D. Watson |
Identity & sources. Identity verified against Wikidata (Q116665). Election results come from official certified totals and the MIT Election Data and Science Lab; see methodology.
Cite this profile. PolitiFinder, “John A. Mead: election history & vote totals.” https://politifinder.com/p/john-a-mead. Accessed [date].