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1835 Rhode Island U.S. House At-large Election

Rhode Island · 5 candidates · See every 1835 U.S. House race

Who won the 1835 Rhode Island U.S. House At-large Election?

William Sprague won the 1835 Rhode Island U.S. House At-large Election. William Sprague received 3,924 popular votes (25.47%). The main challenger was Dutee Pearce (25.32%).

See the full head-to-head between Sprague and Pearce

Sprague +0.1 pts · won by 23 votes
William SpragueDemocraticWINNER25.47%
3,924 votes
Dutee PearceDemocraticWINNER25.32%
3,901 votes
Burgeswhig24.51%
3,776 votes
Cranstonwhig23.75%
3,659 votes
RuyersIndependent0.66%
101 votes
Popular-vote totals for this U.S. House election come from the Constituency-Level Elections Archive (CLEA) and the official public record.

Data last verified July 28, 2026.